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Expert method to solve the 3x3x3 Rubik’s cube

If you want to solve the cube using only 40 (say: fourty) moves – you are at the right site. I am talking about the number of moves on average, of course!
The essential advantage of my system is that you can use it in speedcubing!

In speedcubing you use about 47 moves – this lets you solve the cube in 15! (estimated) seconds (on average, of course). Below I present my method.

Probably you think you will need to learn thousands of formulas... No! That is not necessary! In my system you need only 300 (say: three hundred) formulas! Not even 301. Exactly 300! Is this impossible?

Most speedcubists who use layer by layer method solve F2L (first two layers) in two steps and then solve the last layer (two more steps). They are convinced that the only way to decrease the number of moves (except of improving solving F2L) is to solve last layer in one step (1212 formulas). Speedcubists know what I am talking about. They would like to inculcate these formulas but it is practically impossible!

Let us suppose F2L without one edge and one corner are solved.

Let us consider most popular (professional) system:

 

edge

corner

F2L last element to solve

last F2L edge to solve

last F2L corner to solve

orientation

last four edges orientation

last four corners orientation

permutation

last four edges permutation

last four corners permutation

First step (not shown in the picture above) is: F2L without one edge and one corner.
Yellow means second step: F2L last edge and corner.
Green means third step: orientation of last four edges and corners.
Blue means fourth step: permutation of last four edges and corners.

Another professional system (used by me before) looks as follows:

 

edge

corner

F2L last element to solve

last F2L edge to solve

last F2L corner to solve

orientation

last four edges orientation

last four corners orientation

permutation

last four edges permutation

last four corners permutation

First step (not shown in the picture above) is: F2L without one edge and one corner – no change.
Yellow means second step: F2L last edge and corner – no change.
Green means third step: orientation and permutation of last four edges.
Blue means fourth step: orientation and permutation of last four corners.

Now look how the new system looks from this point of view:

 

edge

corner

F2L last element to solve

last F2L edge to solve

last F2L corner to solve

orientation

last four edges orientation

last four corners orientation

permutation

last four edges permutation

last four corners permutation

First step (not shown in the picture above) is: F2L without one edge and one corner – no change.
Yellow means second step: F2L last edge and corner + last four edges orientation – a big change.
Green means third step: last four edges permutation + orientation and permutation of last four corners – also a big change.
Blue... there is no fourth step!

I was thinking very intensively about my new system for a long time – about one year (2001/2002). Many systems, which I was trying to modify or create, were blind alleys. This system is a quintessence of my searches and experiences. This system, I think, is a golden mean between:
- minimizing the number of moves,
- speedcubing and
- acceptable for human brain number of formulas.

The table below shows the number of moves required for solving separate steps of my system:

 

average number of moves

First step

18,5

Second step

7,45

Third step

12,08

SubTotal

38

additional moves between steps

2

Total

40

The table below shows the number of moves in speedcubing and times required for solving separate steps of my system:

 

number of moves
in speedcubing

time [seconds]

Cross

6

2

3 x pair (corner & edge)

3 x 6,5

3 x 2

Second step

7,45

3

Third step

12,08

4

Total

 

15

The table below shows the number of formulas required for solving separate steps of my system:

 

number of formulas

number of formulas
with reverse ones

number of formulas
with reverse ones and
symmetrical ones

First step

none

none

none

Second step

125 (minus 1 solved)

158 (minus 1 solved)

306 (minus 1 solved)

Third step

177 (minus 1 solved)

270 (minus 1 solved)

493 (minus 1 solved)

Total

300

 

 

For comfort I prepared 158 formulas (with reverse versions) of the second step.

Below are concretes:

step 1 – F2L without one edge and one corner

step 2 – F2L last edge and corner and last four edges orientation

step 3 – last four edges permutation and last four corners orientation/permutation

If you see any mistakes or “dislogicals” in this system, please write to me! Also mistakes in my english language. I am only a human.
I use this system in practice. I would be very glad, if YOU! tried to put my system into practice, too. I wonder your experience with it. Good luck!

Zbigniew Zborowski
Poland Europe
email address: zbigniew_zborowski@poczta.onet.pl
www address: http://www.zborowski.republika.pl/

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